Schema 教程第20课:合并来自不同来源的用户数据
第20课:合并来自不同来源的用户数据
在上一个教程课程中,我们了解到可以从 Mailchimp 的 REST API 获取用户数据,并将其与存储在网站中的用户数据进行合并。
我们可以将这一思路推广,应用于任意两个数据来源,将它们的数据集合并为一个,然后使用合并后的数据执行某些操作。
合并来自不同来源的数据集
函数字段 _arrayInnerJoinJSONObjectProperties(由 PHP Functions Via Schema 扩展提供)允许我们将引用同一实体的 JSON 对象合并为包含所有属性的单个 JSON 对象。
两个来源中的 JSON 对象可以通过"索引"属性具有相同的值来识别为引用同一实体。
在此 GraphQL query 中,source 和 target 输入接收共享公共 email 属性的 JSON 对象列表(因此用作"索引"):
query {
_arrayInnerJoinJSONObjectProperties(
source: [
{
email: "abracadabra@ganga.com",
lang: "de"
},
{
email: "longon@caramanon.com",
lang: "es"
},
{
email: "rancotanto@parabara.com",
lang: "en"
},
{
email: "quezarapadon@quebrulacha.net",
lang: "fr"
},
{
email: "test@test.com",
lang: "de"
},
{
email: "emilanga@pedrola.com",
lang: "fr"
}
],
target: [
{
email: "quezarapadon@quebrulacha.net",
name: "Abrigail Ataluncha"
},
{
email: "abracadabra@ganga.com",
name: "Chip Bennett"
},
{
email: "contributor@test.com",
name: "Contributor"
},
{
email: "longon@caramanon.com",
name: "Emil Uzelac"
},
{
email: "rancotanto@parabara.com",
name: "Lance Ampsrong"
},
{
email: "leo@getpop.org",
name: "leo"
},
{
email: "test@test.com",
name: "Test"
},
{
email: "emilanga@pedrola.com",
name: "Theme Demos"
}
],
index: "email"
)
}当源和目标 JSON 对象中的 email 属性值相同时,这些对象将在结果列表中合并:
{
"data": {
"_arrayInnerJoinJSONObjectProperties": [
{
"email": "quezarapadon@quebrulacha.net",
"name": "Abrigail Ataluncha",
"lang": "fr"
},
{
"email": "abracadabra@ganga.com",
"name": "Chip Bennett",
"lang": "de"
},
{
"email": "contributor@test.com",
"name": "Contributor"
},
{
"email": "longon@caramanon.com",
"name": "Emil Uzelac",
"lang": "es"
},
{
"email": "rancotanto@parabara.com",
"name": "Lance Ampsrong",
"lang": "en"
},
{
"email": "leo@getpop.org",
"name": "leo"
},
{
"email": "test@test.com",
"name": "Test",
"lang": "de"
},
{
"email": "emilanga@pedrola.com",
"name": "Theme Demos",
"lang": "fr"
}
]
}
}我们可以检索存储在多个基于云的服务(通过这些服务的 API 访问)中的数据,并将这些分散的数据集合并在一起。
例如,从以下可能存储用户数据的服务中任意选择两个:
- Mailchimp
- Dropbox
- GitHub
- Microsoft Teams
- Slack
- Trello
- Google Drive
- 您的 WordPress 网站
- 您公司的内部应用程序
- 等等
下面的 GraphQL query 合并了来自两个假设服务的数据集:
- 邮件订阅系统(存储订阅者数据,包括电子邮件和使用语言)
- CRM(存储客户数据,包括姓名和电子邮件)
它首先从邮件订阅服务检索所有记录并提取电子邮件地址。然后使用这些电子邮件地址生成 CRM REST API 的端点 URL,以便仅获取这些用户的数据。最后,以共享的 email 属性为基准将两个数据集合并为一个:
query ProvideNewsletterUserData {
userList: _sendJSONObjectCollectionHTTPRequest(
input: {
url: "https://newapi.getpop.org/wp-json/newsletter/v1/subscriptions"
}
)
@export(as: "userList")
userEmails: _echo(value: $__userList)
@underEachArrayItem(passValueOnwardsAs: "userListItemForEmail")
@applyField(
name: "_objectProperty",
arguments: {
object: $userListItemForEmail,
by: {
key: "email"
}
},
setResultInResponse: true
)
@export(as: "userEmails")
}
query CombineUserDataFromDisparateSources
@depends(on: "ProvideNewsletterUserData")
{
joinedUserEmails: _arrayJoin(
array: $userEmails,
separator: "&emails[]="
)
userEndpoint: _strAppend(
after: "https://newapi.getpop.org/users/api/rest/?query={name%20email}&emails[]=",
append: $__joinedUserEmails
)
userEndpointDataItems: _sendJSONObjectCollectionHTTPRequest(
input: {
url: $__userEndpoint
}
)
userData: _arrayInnerJoinJSONObjectProperties(
source: $__userEndpointDataItems,
target: $userList,
index: "email"
)
@export(as: "userData")
}...生成结果如下:
{
"data": {
"userList": [
{
"email": "abracadabra@ganga.com",
"lang": "de"
},
{
"email": "longon@caramanon.com",
"lang": "es"
},
{
"email": "rancotanto@parabara.com",
"lang": "en"
},
{
"email": "quezarapadon@quebrulacha.net",
"lang": "fr"
},
{
"email": "test@test.com",
"lang": "de"
},
{
"email": "emilanga@pedrola.com",
"lang": "fr"
}
],
"userEmails": [
"abracadabra@ganga.com",
"longon@caramanon.com",
"rancotanto@parabara.com",
"quezarapadon@quebrulacha.net",
"test@test.com",
"emilanga@pedrola.com"
],
"joinedUserEmails": "abracadabra@ganga.com&emails[]=longon@caramanon.com&emails[]=rancotanto@parabara.com&emails[]=quezarapadon@quebrulacha.net&emails[]=test@test.com&emails[]=emilanga@pedrola.com",
"userEndpoint": "https://newapi.getpop.org/users/api/rest/?query={name%20email}&emails[]=abracadabra@ganga.com&emails[]=longon@caramanon.com&emails[]=rancotanto@parabara.com&emails[]=quezarapadon@quebrulacha.net&emails[]=test@test.com&emails[]=emilanga@pedrola.com",
"userEndpointDataItems": [
{
"name": "Abrigail Ataluncha",
"email": "quezarapadon@quebrulacha.net"
},
{
"name": "Chip Bennett",
"email": "abracadabra@ganga.com"
},
{
"name": "Contributor",
"email": "contributor@test.com"
},
{
"name": "Emil Uzelac",
"email": "longon@caramanon.com"
},
{
"name": "Lance Ampsrong",
"email": "rancotanto@parabara.com"
},
{
"name": "leo",
"email": "leo@getpop.org"
},
{
"name": "Test",
"email": "test@test.com"
},
{
"name": "Theme Demos",
"email": "emilanga@pedrola.com"
}
],
"userData": [
{
"email": "abracadabra@ganga.com",
"lang": "de",
"name": "Chip Bennett"
},
{
"email": "longon@caramanon.com",
"lang": "es",
"name": "Emil Uzelac"
},
{
"email": "rancotanto@parabara.com",
"lang": "en",
"name": "Lance Ampsrong"
},
{
"email": "quezarapadon@quebrulacha.net",
"lang": "fr",
"name": "Abrigail Ataluncha"
},
{
"email": "test@test.com",
"lang": "de",
"name": "Test"
},
{
"email": "emilanga@pedrola.com",
"lang": "fr",
"name": "Theme Demos"
}
]
}
}